Matrix Problem Set
Instructions
Complete all problems showing your work. For matrix calculations, show each step clearly. You may use R to verify your answers, but show the mathematical steps first.
Problem 1
Given the following matrices:
\[\mathbf{A} = \begin{bmatrix} 1 & 3 & -2 \\ 4 & 0 & 5 \end{bmatrix}, \quad \mathbf{B} = \begin{bmatrix} 2 & 1 \\ -1 & 3 \\ 0 & 4 \end{bmatrix}, \quad \mathbf{C} = \begin{bmatrix} 3 & -1 \\ 2 & 6 \end{bmatrix}\]
a) What are the dimensions of each matrix?
b) Which of the following operations are possible? If possible, state the dimensions of the result:
\(\mathbf{A} + \mathbf{B}\)
\(\mathbf{A} \times \mathbf{B}\)
\(\mathbf{B} \times \mathbf{C}\)
\(\mathbf{C} \times \mathbf{B}\)
c) Calculate \(\mathbf{A} \times \mathbf{B}\) (show all steps).
Problem 2
Given \(\mathbf{P} = \begin{bmatrix} 2 & -1 & 4 \\ 3 & 0 & 1 \end{bmatrix}\) and \(\mathbf{Q} = \begin{bmatrix} 1 & 2 \\ -1 & 3 \\ 0 & 1 \end{bmatrix}\)
a) Find \(\mathbf{P}^T\) and \(\mathbf{Q}^T\).
b) Calculate \(\mathbf{P} \times \mathbf{Q}\).
c) Calculate \((\mathbf{P} \times \mathbf{Q})^T\).
d) Calculate \(\mathbf{Q}^T \times \mathbf{P}^T\) and verify that \((\mathbf{P} \times \mathbf{Q})^T = \mathbf{Q}^T \times \mathbf{P}^T\).
Problem 3
a) Find the inverse of \(\mathbf{R} = \begin{bmatrix} 3 & 1 \\ 2 & 1 \end{bmatrix}\).
b) Verify your answer by showing that \(\mathbf{R} \times \mathbf{R}^{-1} = \mathbf{I}\).
c) Explain why the matrix \(\mathbf{S} = \begin{bmatrix} 2 & 4 \\ 1 & 2 \end{bmatrix}\) does not have an inverse.
Problem 4
a) Find \(\frac{\partial}{\partial \mathbf{x}}(\mathbf{a}^T\mathbf{x})\) where \(\mathbf{a} = \begin{bmatrix} 3 \\ -2 \\ 1 \\ 4 \end{bmatrix}\) and \(\mathbf{x} = \begin{bmatrix} x_1 \\ x_2 \\ x_3 \\ x_4 \end{bmatrix}\).
b) If \(f(\mathbf{x}) = 2x_1 - 5x_2 + 3x_3\), write this in the form \(\mathbf{c}^T\mathbf{x}\) and find \(\frac{\partial f}{\partial \mathbf{x}}\).
Problem 5
Consider the quadratic form \(\mathbf{x}^T\mathbf{A}\mathbf{x}\) where \(\mathbf{A} = \begin{bmatrix} 2 & 3 \\ 1 & 4 \end{bmatrix}\) and \(\mathbf{x} = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix}\).
a) Expand \(\mathbf{x}^T\mathbf{A}\mathbf{x}\) into scalar form.
b) Find \(\mathbf{A}^T\) and calculate \(\mathbf{A} + \mathbf{A}^T\).
c) Use the derivative rule to find \(\frac{\partial}{\partial \mathbf{x}}(\mathbf{x}^T\mathbf{A}\mathbf{x})\).
Problem 6
Let \(\mathbf{B} = \begin{bmatrix} 4 & -1 & 2 \\ -1 & 3 & 0 \\ 2 & 0 & 5 \end{bmatrix}\) and \(\mathbf{x} = \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix}\).
a) Verify that \(\mathbf{B}\) is symmetric.
b) Find \(\frac{\partial}{\partial \mathbf{x}}(\mathbf{x}^T\mathbf{B}\mathbf{x})\) using the symmetric matrix rule.
c) What would be the result if we used the general rule \((\mathbf{A} + \mathbf{A}^T)\mathbf{x}\) instead? Show that both methods give the same answer.
Problem 7
Consider the expression \(g(\mathbf{x}) = \mathbf{b}^T\mathbf{A}\mathbf{x}\) where: \[\mathbf{b} = \begin{bmatrix} 2 \\ -1 \\ 3 \end{bmatrix}, \quad \mathbf{A} = \begin{bmatrix} 1 & 0 & 2 \\ 3 & -1 & 1 \\ 0 & 2 & 4 \end{bmatrix}, \quad \mathbf{x} = \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix}\]
a) What is the dimension of \(g(\mathbf{x})\)? (Is it a scalar, vector, or matrix?)
b) Use the rule \(\frac{\partial}{\partial \mathbf{x}}(\mathbf{b}^T\mathbf{A}\mathbf{x}) = \mathbf{A}^T\mathbf{b}\) to find \(\frac{\partial g}{\partial \mathbf{x}}\).
c) Calculate \(\mathbf{A}\mathbf{x}\) first, then compute \(\mathbf{b}^T(\mathbf{A}\mathbf{x})\) to expand \(g(\mathbf{x})\) into scalar form.
d) Verify your answer from part (b) by taking partial derivatives of the scalar form from part (c).
Bonus Challenge
Hat Matrix Connection: In linear regression, we minimize the sum of squared errors: \[SSE = (\mathbf{y} - \mathbf{X}\boldsymbol{\beta})^T(\mathbf{y} - \mathbf{X}\boldsymbol{\beta})\]
Expand this expression and identify which derivative rules from this problem set you would need to find \(\frac{\partial SSE}{\partial \boldsymbol{\beta}}\). You don’t need to solve it completely, just identify the relevant derivative rules and explain how they would be applied.